How do you factor #2x^2+22x+56#?

1 Answer
Jim G.
May 14, 2017

#2(x+4)(x+7)#

Explanation:

#"take out a "color(blue)"common factor"" of 2"#

#rArr2(x^2+11x+28)#

#"to factor the quadratic 'split' the x term"#

#"that is " x^2+4x+7x+28#

#"factorising each 'pair' gives"#

#color(red)(x)(x+4)color(red)(+7)(x+4)#

#"take out the common factor " (x+4)#

#(x+4)(color(red)(x+7))#

#rArr2x^2+22x+56=2(x+4)(x+7)#

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