How do you factor #2x^2-10x-42#?

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How do you factor #2x^2-10x-42#?

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Answer 1 · 2015-10-11T22:23:25

Factor #f(x) = 2x^2 - 10x - 42#

Explanation:

#f(x) = 2y = 2(x^2 - 5x - 21).#
The trinomial #y = x^2 - 5x - 21# can't be factored because its determinant #D = b^2 - 4ac = 25 + 84 = 109# is not a perfect square.
Therefor: #f(x) = 2(x^2 - 5x - 21).#

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How do you factor #2x^2-10x-42#?

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