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How do you factor #2w^3 + 54#?

1 Answer

Dec 19, 2015

#2(w+3)(w^2-3w+9)#

Explanation:

First, factor out a common #2#.

#=2(w^3+27)#

Notice that #(w^3+27)# is a sum of cubes, which follows the rule

#a^3+b^3=(a+b)(a^2-ab+b^2)#

Thus,

#2(w^3+27)=2((w)^3+(3)^3)=2(w+3)(w^2-3w+9)#

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