How do you factor $2n^2 + 3n - 9$ ?

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How do you factor $2n^2 + 3n - 9$ ?

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Answer 1 · 2015-05-19T07:06:04

$2n^2+ 3n -9$

We can Split the Middle Term of this expression to factorise it
In this technique, if we have to factorise an expression like $an^2 + bn + c$ , we need to think of 2 numbers such that:

$N_1*N_2 = a*c = 2 xx (-9) = -18$
and
$N_1 +N_2 = b = 3$

After trying out a few numbers we get $N_1 = 6$ and $N_2 =-3$

$6 xx (-3) = -18$ and $6+(-3)= 3$

$2n^2+ 3n -9 = 2n^2+ 6n - 3n -9$

$= 2n(n +3) -3(n+3)$

$=color(green)((2n - 3)(n +3)$

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How do you factor $2n^2 + 3n - 9$ ?

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