How do you factor 2k³+3k²+6k+9?

1 Answer
Jim G.
May 28, 2018

(2k+3)(k^2+3)

Explanation:

color(blue)"factor by grouping"

=color(red)(k^2)(2k+3)color(red)(+3)(2k+3)

"take out the "color(blue)"common factor "(2k+3)

=(2k+3)(color(red)(k^2+3))

2k^3+3k^2+6k+9=(2k+3)(k^2+3)

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