Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you factor #27-t^3#?

↳Redirected from "Question #b6ba3"

1 Answer

Oct 9, 2015

#(3-t)(9+3t+t^2)#

Explanation:

#27-t^3=># use difference of cubes formula:

#a^3-b^3=(a-b)(a^2+ab+b^2)=># so in this case we have:

#(3^3-t^3)=(3-t)(9+3t+t^2)#

Related questions

See all questions in Factoring Completely

Impact of this question

2448 views around the world

You can reuse this answer
Creative Commons License