How do you factor #27-t^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer iceman Oct 9, 2015 #(3-t)(9+3t+t^2)# Explanation: #27-t^3=># use difference of cubes formula: #a^3-b^3=(a-b)(a^2+ab+b^2)=># so in this case we have: #(3^3-t^3)=(3-t)(9+3t+t^2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1927 views around the world You can reuse this answer Creative Commons License