How do you factor $25 z^{2} - 36 b^{2}$ $25z^2 - 36b^2$ ?

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Answer 1 · 2016-03-20T16:31:55

$= (5 z + 6 b) (5 z - 6 b)$ $=color(blue)((5z + 6b) (5z - 6b)$

$25 z^{2} - 36 b^{2}$ $25 z^2 - 36b^2$

The expression can also be written as:
${(5 z)}^{2} - {(6 b)}^{2}$ $(5 z) ^2 - (6b)^2$

This is of the form :
$a^{2} - b^{2} = (a + b) (a - b)$ $color(blue)(a^2 - b ^2 = (a+b)(a-b)$

${(5 z)}^{2} - {(6 b)}^{2} = (5 z + 6 b) (5 z - 6 b)$ $(5 z) ^2 - (6b)^2 = color(blue)((5z + 6b) (5z - 6b)$

The factorised form of the expression is:
$(5 z + 6 b) (5 z - 6 b)$ $color(blue)((5z + 6b) (5z - 6b)$

How do you factor 25z^2 - 36b^225z2−36b2 25z^2 - 36b^2?