How do you factor #24a^2 - 150b^2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Meave60 Nov 15, 2015 #24a^2-150b^2=6(2a+5b)(2a-5b)# Explanation: #24a^2-150b^2# Factor out the GCF #6#. #6(4a^2-25b^2)# #(4a^2-25b^2)# fits the difference of squares, #a^2-b^2=(a+b)(a-b)#, where #a=2a and b=5b#. #6((2a)^2-(5b)^2)=6(2a+5b)(2a-5b)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1178 views around the world You can reuse this answer Creative Commons License