How do you factor #216x^3+1#?
1 Answer
Mar 24, 2017
Explanation:
This is a
#color(blue)"sum of cubes"# which is factorised, in general, as
#color(red)(bar(ul(|color(white)(2/2)color(black)(a^3+b^3=(a+b)(a^2-ab+b^2))color(white)(2/2)|)))#
#216x^3+1=(6x)^3+1^3#
#rArra=6x" and " b=1#
#rArr216x^3+1=(6x+1)(36x^2-6x+1)#
