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How do you factor #16m^4 - 81#?

1 Answer

May 30, 2015

#16m^4-81#

Factorize:
#=(4m^2)^2-(9)^2#

Recall: #(a)^2-(b)^2=(a+b)(a-b)#

#=(4m^2+9)(4m^2-9)#
#=(4m^2+9)[(2m)^2-(3)^2]#

ANSWER:
#color(green)[=(4m^2+9)(2m+3)(2m-3)#

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