How do you factor # 16-1/4k^2#?
1 Answer
Sep 23, 2016
Explanation:
The difference of squares identity can be written:
#a^2-b^2 = (a-b)(a+b)#
Note that
So we find:
#16 - 1/4k^2 = 4^2-(1/2k)^2 = (4-1/2k)(4+1/2k)#
