How do you factor $14 x^{3} - 21 x$ $14x^3 - 21x$ ?

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Answer 1 · 2018-07-22T08:39:52

$7 x (\sqrt{2} x + \sqrt{3}) (\sqrt{2} x - \sqrt{3})$ $7x(\sqrt2x+\sqrt3)(\sqrt2x-\sqrt3)$

$14 x^{3} - 21 x$ $14x^3-21x$

$= 7 x (2 x^{2} - 3)$ $=7x(2x^2-3)$

$= 7 x ({(\sqrt{2} x)}^{2} - {(\sqrt{3})}^{2})$ $=7x((\sqrt2x)^2-(\sqrt3)^2)$

$= 7 x (\sqrt{2} x + \sqrt{3}) (\sqrt{2} x - \sqrt{3})$ $=7x(\sqrt2x+\sqrt3)(\sqrt2x-\sqrt3)$

Answer 2 · 2018-07-22T08:41:10

$7 x (2 x^{2} - 3)$ $7x (2x^2 - 3)$

$14 x^{3}$ $14x^3$ & $21 x :$ $21x :$ The GCF (Greatest Common Factor) is $7 x$ $7x$

Factor out the greatest common factor:
$14 x^{3} - 21 x = 7 x (2 x^{2} - 3)$ $14x^3 - 21x = 7x (2x^2 - 3)$

How do you factor 14x^3 - 21x14x3−21x14x^3 - 21x?