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How do you factor #12x²-27#?

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May 31, 2015

#12x^2-27 = 3(4x^2-9)#

#= 3((2x)^2-3^2) = 3(2x-3)(2x+3)#

...using the difference of squares identity:

#a^2-b^2 = (a-b)(a+b)#

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