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How do you factor #12a^2 - 4ac + 3ab - bc#?

1 Answer

May 12, 2015

Let us try grouping and spotting common factors:

#12a^2 - 4ac + 3ab - bc = (12a^2 - 4ac) + (3ab - bc)#

#= (4a*3a - 4a*c) + (b*3a - b*c)#

#= 4a(3a-c) + b(3a-c)#

#= (4a + b)(3a - c)#

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