How do you factor #125x^3-64y^3 #? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Steve M Oct 4, 2016 This is the difference of two cubes, ie #X^3-Y^3 = (X-Y)(X^2+XY+Y^2)# (Learn This) Explanation: #125x^3−64y^3=(5x)^3-(4y)^3# #=(5x-4y)((5x)^2+(5x)(4y)+(4y)^2)# #=(5x-4y)(25x^2+20xy+16y^2)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 36265 views around the world You can reuse this answer Creative Commons License