How do you factor #125x^3+1/125#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Ratnaker Mehta Apr 14, 2018 #125x^3+1/125=(5x+1/5)(25x^2-x+1/25)#. Explanation: Recall that, #a^3+b^3=(a+b)(a^2-ab+b^2)#. With #a=5x, and, b=1/5#, we get, #125x^3+1/125=(5x+1/5)(25x^2-x+1/25)#. Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1995 views around the world You can reuse this answer Creative Commons License