How do you factor #125 - x^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Gerardina C. Jun 6, 2016 #125-x^3=(5-x)(25+5x+x^2)# Explanation: because of the known identity #a^3-b^3=(a-b)(a^2+ab+b^2)# we have #125-x^3=(5-x)(25+5x+x^2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 4193 views around the world You can reuse this answer Creative Commons License