How do you factor 10x^2+23x+6 ?

1 Answer
Nghi N.
Apr 12, 2016

(10x + 3)(x + 2)

Explanation:

Use the new systematic, non-guessing AC Method (Socratic Search)
y = 10x^2 + 23x + 6 = 10(x + p)(x + q)
Converted trinomial: y' = x^2 + 23x + 60 =(x + p')(x + q').
p' and q' have same sign because ac > 0.
Factor pairs of (ac = 60) --> (2, 30)(3, 20). This last sum is 23 = b.
Then, p = (p')/a = 3/10 and q = (q')/a = 20/10 = 2

Factored form: y = 10(x + 3/10)(x + 2) = (10x + 3)(x + 2)

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