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How do you express # x/ (x^3-2x^2+x)# in partial fractions?

1 Answer

Dec 25, 2016

The answer is #=1/(x-1)^2#

Explanation:

We need

#(a-b)^2=a^2-2ab+b^2#

Let's factorise the denominator

#x^3-2x^2+x=x(x^2-2x+1)=x(x-1)^2#

So,

#x/(x^3-2x^2+x)=cancelx/(cancelx(x-1)^2)=1/(x-1)^2#

Fraction is already in irreductible form

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