How do you express #(x^3)/(x^3+1)# in partial fractions?

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How do you express #(x^3)/(x^3+1)# in partial fractions?

↳Redirected from "Suppose that I don't have a formula for #g(x)# but I know that #g(1) = 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"

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Answer 1 · 2016-10-18T12:04:03

#=1-1/(x^3+1)#

Explanation:

Just do a division
#x^3/(x^3+1)=1-1/(x^3+1)#

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How do you express #(x^3)/(x^3+1)# in partial fractions?

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