How do you express $sin(pi/ 8 ) * cos(( 5 pi)/8 )$ without products of trigonometric functions?

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How do you express $sin(pi/ 8 ) * cos(( 5 pi)/8 )$ without products of trigonometric functions?

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Answer 1 · 2016-03-25T12:09:01

$- sin^2 (pi/8)$

Explanation:

Trig unit circle and the property of complementary arcs give -->
$cos ((5pi)/8) = cos (pi/8 + (4pi)/8) = cos (pi/8 + pi/2) = - sin (pi/8)$
Therefor, the product can be expressed as:
$P = sin (pi/8).cos ((5pi)/8) = - sin^2 (pi/8)$

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How do you express $sin(pi/ 8 ) * cos(( 5 pi)/8 )$ without products of trigonometric functions?

1 Answer

Explanation:

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How do you express $sin(pi/ 8 ) * cos(( 5 pi)/8 )$ without products of trigonometric functions?