How do you express $sin(pi/ 8 ) * cos(( 13 pi)/8 )$ without products of trigonometric functions?

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How do you express $sin(pi/ 8 ) * cos(( 13 pi)/8 )$ without products of trigonometric functions?

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Answer 1 · 2016-03-03T16:14:14

$P = sin^2 (pi/8)$

Explanation:

On the trig unit circle,
$cos ((13pi)/8) = cos ((-3pi)/8 + 2pi) = cos ((-3pi)/8) = cos ((3pi)/8)$
$= cos ((4pi)/8 - pi/8) = cos (pi/2 - pi/8) = sin (pi/8)$
Therefor, the expression can be reduced to -->
$P = sin (pi/8).cos((13pi)/8) = sin^2 (pi/8)$

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How do you express $sin(pi/ 8 ) * cos(( 13 pi)/8 )$ without products of trigonometric functions?

1 Answer

Explanation:

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How do you express $sin(pi/ 8 ) * cos(( 13 pi)/8 )$ without products of trigonometric functions?