How do you express $sin (\frac{π}{6}) \cdot cos (\frac{π}{2})$ $sin(pi/ 6 ) * cos( ( pi) / 2 )$ without using products of trigonometric functions?

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Answer 1 · 2016-03-23T23:41:13

$cos (\frac{π}{2}) = 0$ $\cos (\pi/2)=0$ so any product involving it is automatically 0.

How do you express sin(π6)⋅cos(π2)sin(pi/ 6 ) * cos( ( pi) / 2 ) without using products of trigonometric functions?