How do you express $sin (\frac{π}{6}) \cdot cos (\frac{3 π}{2})$ $sin(pi/ 6 ) * cos( (3 pi) / 2 )$ without using products of trigonometric functions?

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Answer 1 · 2016-07-26T22:13:13

$0$ $0$

$sin (\frac{π}{6}) = \frac{1}{2}$ $sin(pi/6) = 1/2$

$cos (\frac{3 π}{2}) = 0$ $cos((3pi)/2) = 0$

So:

$sin (\frac{π}{6}) \cdot cos (\frac{3 π}{2}) = \frac{1}{2} \cdot 0 = 0$ $sin(pi/6)*cos((3pi)/2) = 1/2*0 = 0$

How do you express sin(pi/ 6 ) * cos( (3 pi) / 2 ) sin(π6)⋅cos(3π2)sin(pi/ 6 ) * cos( (3 pi) / 2 ) without using products of trigonometric functions?