Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you express #sin(pi/ 4 ) * sin( ( pi) / 8 ) # without using products of trigonometric functions?

1 Answer

Jun 10, 2017

#(sqrt2*sqrt(2-sqrt2))/4#

Explanation:

Use the identity: #sin(pi/4)=(sqrt2)/2#

#sin(pi/8)=sqrt((2-sqrt2)/4)#

Hence,

#sin(pi/4)*sin(pi/8)=(sqrt2)/2*sqrt((2-sqrt2)/4)#
#color(white)(xxxxxxxxxxx.)=(sqrt2*sqrt(2-sqrt2))/4#

Related questions

See all questions in Products, Sums, Linear Combinations, and Applications

Impact of this question

1159 views around the world

You can reuse this answer
Creative Commons License