How do you express sin(π12)cos(13π12) without products of trigonometric functions?

1 Answer
Jul 3, 2018

sin(π6)=12

Explanation:

![https://study.com/academy/lesson/http://product-to-sum-identities-uses-applications.html](https://useruploads.socratic.org/2xBiCxzSmmCr1qNXSs2e_trigonometric%20identities.png)

sin(π12)cos(13π12)

sinxcosy=(12)[sin(x+y)+sin(xy])

(12)[sin(π12+13π12)+sin(π1213π12)]

sin(14π12)+sin(π)2

sin(π+π6)sin(π)2

sin(π6)=12