How do you express #sin^4theta - sin^3theta + cos^2theta# in terms of non-exponential trigonometric functions?

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How do you express #sin^4theta - sin^3theta + cos^2theta# in terms of non-exponential trigonometric functions?

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Answer 1 · 2016-07-02T03:26:05

Transform trig expression.

Explanation:

Apply the 2 trig identities:
#cos ^2 t = (1 + cos 2t)/2#
#sin^2 t = (1 - cos 2t)/2#
#sin^4 t - sin^3 t + cos^2 t = sin^2 t(sin t)(sin t - 1) + cos ^2 t =#
#= ((1 - cos 2t)/2) (sin t - 1)sin t + (1 + cos 2t)/2#

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How do you express #sin^4theta - sin^3theta + cos^2theta# in terms of non-exponential trigonometric functions?

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