How do you express sin4θcos3(π2θ) in terms of non-exponential trigonometric functions?

1 Answer
Jun 13, 2016

=14(12cos2θ+12(1+cos4θ)3sinθ+sin3θ)

Explanation:

Given
=sin4θcos3(π2θ)

=sin4θsin3θ

Now we know
sin2θ=12(1cos2θ)
and
sin3θ=14(3sinθsin3θ)

Inserting these values the given expression becomes

=(12(1cos2θ))214(3sinθsin3θ)

=14(12cos2θ+cos22θ3sinθ+sin3θ)

=14(12cos2θ+12(1+cos4θ)3sinθ+sin3θ)