How do you express $cos(pi/ 4 ) * sin( ( 13 pi) / 8 )$ without using products of trigonometric functions?

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How do you express $cos(pi/ 4 ) * sin( ( 13 pi) / 8 )$ without using products of trigonometric functions?

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Answer 1 · 2016-04-12T11:42:59

$(sin((15pi)/16)+sin((11pi)/16))/2$

Explanation:

Use $sin (A+B)cos(A-B)=(sin 2A + sin 2B)/2 =$
Here, $A+B=13pi/8 and A-B=pi/4$
Add and subtract.
$2A = 15pi/8. A + 15pi/16. 2B = 11pi/8. B = 11pi/16$ .
Answer: $(sin((15pi)/16)+sin((11pi)/16))/2$

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How do you express $cos(pi/ 4 ) * sin( ( 13 pi) / 8 )$ without using products of trigonometric functions?

1 Answer

Explanation:

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Math

Humanities

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How do you express cos(pi/ 4 ) * sin( ( 13 pi) / 8 ) cos(pi/ 4 ) * sin( ( 13 pi) / 8 ) without using products of trigonometric functions?

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Explanation:

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How do you express $cos(pi/ 4 ) * sin( ( 13 pi) / 8 )$ without using products of trigonometric functions?