How do you express $cos(pi/ 3 ) * sin( ( pi) / 6 )$ without using products of trigonometric functions?

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Answer 1 · 2016-05-13T03:15:19

$(1/4)$

$y = cos (pi/3).sin (pi/6)$
Trig table --> $cos (pi/3) = 1/2.$ and $sin (pi/6) = 1/2$
Therefor, y can be expressed as: $y = (1/2)(1/2) = 1/4$

How do you express cos(pi/ 3 ) * sin( ( pi) / 6 ) cos(pi/ 3 ) * sin( ( pi) / 6 ) without using products of trigonometric functions?