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How do you express #cos(pi/ 3 ) * sin( ( pi) / 6 ) # without using products of trigonometric functions?

1 Answer

May 13, 2016

#(1/4)#

Explanation:

#y = cos (pi/3).sin (pi/6)#
Trig table --> #cos (pi/3) = 1/2.# and #sin (pi/6) = 1/2#
Therefor, y can be expressed as: #y = (1/2)(1/2) = 1/4#

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