How do you express $cos(pi/ 3 ) * sin( ( 5 pi) / 6 )$ without using products of trigonometric functions?

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How do you express $cos(pi/ 3 ) * sin( ( 5 pi) / 6 )$ without using products of trigonometric functions?

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Answer 1 · 2016-05-26T19:12:50

$(1/2)sin (pi/6)$

Explanation:

$P = cos (pi/3).sin ((5pi)/6)$
Trig table -->
$cos (pi/3) = 1/2$
Unit circle, property of supplementary arcs -->
$sin ((5pi)/6) = sin (pi - pi/6) = sin (pi/6)$
P can be expressed as:
$P = (1/2)sin (pi/6)$

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How do you express $cos(pi/ 3 ) * sin( ( 5 pi) / 6 )$ without using products of trigonometric functions?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you express cos(pi/ 3 ) * sin( ( 5 pi) / 6 ) cos(pi/ 3 ) * sin( ( 5 pi) / 6 ) without using products of trigonometric functions?

1 Answer

Explanation:

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How do you express $cos(pi/ 3 ) * sin( ( 5 pi) / 6 )$ without using products of trigonometric functions?