How do you express #cos( (5 pi)/6 ) * cos (( 11 pi) /6 ) # without using products of trigonometric functions?

Question

How do you express #cos( (5 pi)/6 ) * cos (( 11 pi) /6 ) # without using products of trigonometric functions?

1 Answer

Impact of this question

2058 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-18T01:01:40

#-3/4#

Explanation:

Trig table --> #cos ((5pi)/6) =cos(pi-pi/6)=-cospi/6=-sqrt3/2#
#cos ((11pi)/6) = cos (-pi/6 + (12pi)/6) = cos (-pi/6 + 2pi) = #
#cos (-pi/6) = cos (pi/6) = sqrt3/2#
The product can be expressed as:
#P = (-sqrt3/2)(sqrt3/2) = - 3/4#

Science

Math

Humanities

... and beyond

How do you express #cos( (5 pi)/6 ) * cos (( 11 pi) /6 ) # without using products of trigonometric functions?

1 Answer

Explanation:

Related questions

Impact of this question