How do you express $cos( (5 pi)/6 ) * cos (( 11 pi) /12 )$ without using products of trigonometric functions?

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How do you express $cos( (5 pi)/6 ) * cos (( 11 pi) /12 )$ without using products of trigonometric functions?

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Answer 1 · 2016-09-13T03:21:31

$P = cos ((5pi)/6).cos ((11pi)/12)$
Trig table of special arcs, and unit circle -->
$cos ((5pi)/6) = - sqrt3/2$
$cos ((11pi)/12) = cos ((- pi/12) + pi) = - cos (-pi/12) = - cos (pi/12)$
P can be expressed as:
$P = (sqrt3/2).cos (pi/12)$

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How do you express $cos( (5 pi)/6 ) * cos (( 11 pi) /12 )$ without using products of trigonometric functions?

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How do you express cos( (5 pi)/6 ) * cos (( 11 pi) /12 ) cos( (5 pi)/6 ) * cos (( 11 pi) /12 ) without using products of trigonometric functions?

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How do you express $cos( (5 pi)/6 ) * cos (( 11 pi) /12 )$ without using products of trigonometric functions?