How do you express $cos (\frac{5 π}{4}) \cdot cos (\frac{π}{6})$ $cos( (5 pi)/4 ) * cos (( pi) /6 )$ without using products of trigonometric functions?

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How do you express $cos (\frac{5 π}{4}) \cdot cos (\frac{π}{6})$ $cos( (5 pi)/4 ) * cos (( pi) /6 )$ without using products of trigonometric functions?

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Answer 1 · 2016-03-05T06:07:52

$- \frac{\sqrt{6}}{4}$ $-sqrt6/4$

Explanation:

Trig table, and unit circle -->
$cos (\frac{π}{6}) = \frac{\sqrt{3}}{2}$ $cos (pi/6) = sqrt3/2$
$cos (\frac{5 π}{4}) = cos (\frac{π}{4} + π) = - cos (\frac{π}{4}) = - \frac{\sqrt{2}}{2}$ $cos ((5pi)/4) = cos (pi/4 + pi) = - cos (pi/4) = -sqrt2/2$ .
Product $P = (- \frac{\sqrt{2}}{2}) (\frac{\sqrt{3}}{2}) = - \frac{\sqrt{6}}{4}$ $P = (-sqrt2/2)(sqrt3/2) = -sqrt6/4$

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How do you express $cos (\frac{5 π}{4}) \cdot cos (\frac{π}{6})$ $cos( (5 pi)/4 ) * cos (( pi) /6 )$ without using products of trigonometric functions?

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How do you express cos(5π4)⋅cos(π6)cos( (5 pi)/4 ) * cos (( pi) /6 ) without using products of trigonometric functions?

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How do you express $cos (\frac{5 π}{4}) \cdot cos (\frac{π}{6})$ $cos( (5 pi)/4 ) * cos (( pi) /6 )$ without using products of trigonometric functions?