How do you express a single logarithm for #log_e *M + log_e *T#?

1 Answer
May 20, 2015

There is a rule for logarithms where you can combine a sum of them into one logarithm that multiplies the respective arguments. So:

#log_e(M)+log_e(T) = lnM+lnT = ln(MT)#

Similarly, #log_e(M)-log_e(T) = lnM-lnT = ln(M/T)#