Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you express #(3x )/ (x^2 * (x^2+1) )# in partial fractions?

1 Answer

Shwetank Mauria

May 8, 2016

#(3x)/(x^2*(x^2+1))=3/x-(3x)/(x^2+1)#

Explanation:

#(3x)/(x^2*(x^2+1))=3/(x*(x^2+1)# and let its partial fractions be

#3/(x*(x^2+1))hArrA/x+(Bx+C)/(x^2+1)# or

#3/(x*(x^2+1))hArr(A(x^2+1)+x(Bx+C))/(x*(x^2+1))# or

#3/(x*(x^2+1))hArr(x^2(A+B)+Cx+A)/(x*(x^2+1))# or

#A+B=0#, #C=0# and #A=3#. Thus #B=-3#

Hence #(3x)/(x^2*(x^2+1))=3/x-(3x)/(x^2+1)#

Related questions

See all questions in Partial Fraction Decomposition (Linear Denominators)

Impact of this question

1783 views around the world

You can reuse this answer
Creative Commons License