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How do you express #3/((1 + x)(1 - 2x)) # in partial fractions?

1 Answer

Mar 21, 2016

#3/((1+x)(1-2x)) = 1/(1+x) +2/(1-2x)#

Explanation:

#3/((1+x)(1-2x)) = A/(1+x) +B/(1-2x)#

#3=A(1-2x)+B((1+x)#

#3=A-2Ax+B+Bx#

#A+B=3, -2A+B=0#

#B=3-A->-2A+3-A=0->-3A+3=0#

#-3A=-3,A=1,B=2#

#3/((1+x)(1-2x)) = 1/(1+x) +2/(1-2x)#

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