How do you expand #log sqrt( 100 x^3 )#?

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Answer 1 · 2016-05-06T20:29:31

#log sqrt(100x^3)=1+3/2*log x#

#log sqrt(100x^3)=log 10sqrt(x^3)=log 10*x^(3/2)#

#log a*b=log a+log b#

#log sqrt(100x^3)=log 10+log x^(3/2)#

#log a^b=b*log a#

#log sqrt(100x^3)=log 10+3/2*log x#

#log 10=1#

#log sqrt(100x^3)=1+3/2*log x#