How do you expand ${log}_{6} (6 x)$ $log_6(6x)$ ?

Question

2039 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-23T23:42:24

I found: $1 + {log}_{6} (x)$ $1+log_6(x)$

We can write:
${log}_{6} (6 x) = {log}_{6} (6) + {log}_{6} (x) = 1 + {log}_{6} (x)$ $log_6(6x)=log_6(6)+log_6(x)=1+log_6(x)$

How do you expand log_6(6x)log6(6x)log_6(6x)?