How do you expand #log_6(6x)#? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer GiĆ³ May 23, 2016 I found: #1+log_6(x)# Explanation: We can write: #log_6(6x)=log_6(6)+log_6(x)=1+log_6(x)# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1780 views around the world You can reuse this answer Creative Commons License