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How do you expand #log_2 20#?

1 Answer

A. S. Adikesavan

May 27, 2016

#2 + log 5/log 2=4.322#, nearly.

Explanation:

Use #log_b a = log_c a/log_c b, log_2 a^n=n log_2 a and log_2 2=1#

#log_2 20 = log_2((2^2)5)#

#=log_2 2^2+log_2 5#

#=2 log_2 2+log_2 5#

#= 2(1)+log 5/log 2#

#=4.322, nearly.

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