How do you evaluate #x-(-y)# where x=-2 and y=5?

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1 Answer
smendyka
Jan 11, 2017

Substitute #color(red)(-2)# for #x# and Substitute #color(blue)(5)# for #y# and calculate. See process below:

Explanation:

#color(red)(x) - (-color(blue)(y))# becomes:

#color(red)(-2) - (-color(blue)(5))#

Because in addition and subtract minus a negative number becomes a plus, we can rewrite as:

#color(red)(-2) + color(blue)(5)#

#3#

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