How do you evaluate #w+x+z# if w=6, x=0.4, y=1/2, z=-3? Algebra Expressions, Equations, and Functions Variable Expressions 1 Answer Alan N. Feb 14, 2017 3.4 Explanation: Expression #= w+x+z# Given #w=6, x=0.4, z=-3# [Note: #y=1/2# is irrelevent as #y# does not figure in the evaluation] Expression #= 6+0.4+(-3)# #= 6+0.4-3 = 3.4# Answer link Related questions How do you write the variable expression for: a quotient of 2 and the sum of a number and 3 ? What are variables? What are variable expressions? How do you write variable expressions? How do you evaluate variable expressions? How do you simplify the expression #3x-x+4#? How do you write a quotient of a number and 6 as an expression? How do you evaluate the expression #2x+1# for #x=1#? How do you write a product of a number and 2 as an expression? How do you write 5 less than 2 times a number as a variable expression? See all questions in Variable Expressions Impact of this question 1087 views around the world You can reuse this answer Creative Commons License