How do you evaluate the six trigonometric functions given t=π/6?

1 Answer
Oct 30, 2017

Given t = pi/6 = 30^0

Sin 30 = 1/2

cos 30 = sqrt3/2

tan 30 = 1/sqrt3

csc. 30 = 2/ sin 30 = 2

sec 30 = 1/ cos 30 = 2/sqrt3

cot 30 = 1/ tan 30 = sqrt3

Explanation:

Given t = pi/6 = 30^0

Sin 30 = 1/2

cos 30 = sqrt3/2

tan 30 = 1/sqrt3

csc. 30 = 2/ sin 30 = 2

sec 30 = 1/ cos 30 = 2/sqrt3

cot 30 = 1/ tan 30 = sqrt3