How do you evaluate the integral of #int e^(ln(x^(2)+1))dx# from -2 to -1? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer Konstantinos Michailidis Dec 28, 2015 You have that #int_-2^-1 e^(ln(x^(2)+1))dx=int_-2^-1 (x^2+1)dx=[x^3/3+x]_-2^-1=10/3# We used the following property #e^(lna)=a# Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of #ln(7x)#? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of #x^2-6x+5# from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral #1/(sqrt(49-x^2))# from 0 to #7sqrt(3/2)#? How do you integrate #f(x)=intsin(e^t)dt# between 4 to #x^2#? How do you determine the indefinite integrals? How do you integrate #x^2sqrt(x^(4)+5)#? See all questions in Definite and indefinite integrals Impact of this question 6096 views around the world You can reuse this answer Creative Commons License