How do you evaluate the function $f (x) = x^{3} - 2 x^{2} + 5 x - 8$ $f(x)=x^3-2x^2+5x-8$ for f(-5)?

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Answer 1 · 2017-02-17T22:40:44

Just replace the value of $x$ $x$ with $- 5$ $-5$ in the formula of $f (x)$ $f(x)$

hence

$f (- 5) = {(- 5)}^{3} - 2 {(- 5)}^{2} + 5 (- 5) - 8$ $f(-5)=(-5)^3-2(-5)^2+5(-5)-8$

$f (- 5) = - 125 - 50 - 25 - 8$ $f(-5)=-125-50-25-8$

$f (- 5) = - 208$ $f(-5)=-208$

How do you evaluate the function f(x)=x^3-2x^2+5x-8f(x)=x3−2x2+5x−8f(x)=x^3-2x^2+5x-8 for f(-5)?