How do you evaluate the function f (x) = 3x^2 + 3x -2 for f (a) + f (2)?

1 Answer
Nov 27, 2015

f(a) + f(2) = 3a^2 + 3a + 14

Explanation:

When evaluating a function f(x) at some specific value, you simply replace x with that value wherever x appears in the function.
So

f(a) = 3a^2 + 3a - 2

and

f(2) = 3(2)^2 + 3(2) - 2 = 12+6-2 = 16

Thus

f(a) + f(2) = (3a^2 +3a - 2) + 16 = 3a^2 + 3a + 14