How do you evaluate the definite integral ∫(x+6)2dx from [0,4]? Calculus Introduction to Integration Formal Definition of the Definite Integral 1 Answer Maharshi Feb 12, 2016 7843=261.333 Explanation: ∫(x+6)2=(x+6)33∣0,4=(4+6)33−633=261.333 Answer link Related questions What is the Formal Definition of the Definite Integral of the function y=f(x) over the... How do you use the definition of the definite integral? What is the integral of dy/dx? What is an improper integral? How do you calculate the double integral of (xcos(x+y))dr where r is the region: 0 less than... How do you apply the evaluation theorem to evaluate the integral 3tdt over the interval [0,3]? What is the difference between an antiderivative and an integral? How do you integrate 3x2−5x+9 from 0 to 7? Question #f27d5 How do you evaluate the definite integral ∫√tln(t)dt from 2 to 1? See all questions in Formal Definition of the Definite Integral Impact of this question 1677 views around the world You can reuse this answer Creative Commons License