Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you evaluate the definite integral #int (x-1)^3dx# from [2,3]?

1 Answer

Jan 16, 2018

#int_2^3 (x-1)^3dx = 15/4#

Explanation:

#int_2^3 (x-1)^3dx = int_2^3 (x-1)^3d(x-1)#

#int_2^3 (x-1)^3dx = [(x-1)^4/4]_2^3#

#int_2^3 (x-1)^3dx = (3-1)^4/4 - (2-1)^4/4#

#int_2^3 (x-1)^3dx = (2^4/4-1/4) #

#int_2^3 (x-1)^3dx = (16/4-1/4) =15/4#

Related questions

See all questions in Definite and indefinite integrals

Impact of this question

2440 views around the world

You can reuse this answer
Creative Commons License