How do you evaluate the definite integral int logx dx from [2,4]? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer F. Javier B. Apr 30, 2018 I=6log2-2/ln10. See details below Explanation: I=intlogxdx Lets do it by parts u=logx and dv=dx With this we have du=1/(xln10)dx and v=x I=xlogx-int1/ln10dx=xlogx-1/ln10x=F(x) F(4)-F(2)=4log4-4/(ln10)-2log2+2/ln10=4log4-2log2-2/ln10=4log2^2-2log2-2/ln10=6log2-2/ln10 Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of ln(7x)? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of x^2-6x+5 from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral 1/(sqrt(49-x^2)) from 0 to 7sqrt(3/2)? How do you integrate f(x)=intsin(e^t)dt between 4 to x^2? How do you determine the indefinite integrals? How do you integrate x^2sqrt(x^(4)+5)? See all questions in Definite and indefinite integrals Impact of this question 3965 views around the world You can reuse this answer Creative Commons License