How do you evaluate the definite integral #int (e^x)/(1+e^x)# from #[0,1]#? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer Eddie Sep 13, 2016 #=ln( (1+e)/2)# Explanation: note that #d/dx(ln (1+e^x)) = (e^x)/(1+e^x)# So #int_0^1 (e^x)/(1+e^x) \ dx# #=int_0^1 d/dx(ln (1+e^x)) \ dx# #=[ ln (1+e^x)]_0^1# #=ln( (1+e)/2)# Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of #ln(7x)#? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of #x^2-6x+5# from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral #1/(sqrt(49-x^2))# from 0 to #7sqrt(3/2)#? How do you integrate #f(x)=intsin(e^t)dt# between 4 to #x^2#? How do you determine the indefinite integrals? How do you integrate #x^2sqrt(x^(4)+5)#? See all questions in Definite and indefinite integrals Impact of this question 7352 views around the world You can reuse this answer Creative Commons License